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Step
A
The height of the arch is decided by the size of
an equilateral triangle and the size of a circular arc equal
to a side of the triangle
I = the centre of the original square
II = the height of the arch
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Step
B
The longitudinal arc is constructed as follows.
Arc III is equal to arch II
in step A. The longitudional arc is constructed as
predicted the line IV giving the arc center at
VI as being a perpendicular line (V) from the
center of IV intersecting the transverse axis of the
original square at VI
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Step
C
Any desired transverse crosssection can be
constructed here showing the places of intersection on the
widest places between the base line arcs and ther points of
intersection between base line and cordline VII,
IIX, IX and X
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