It's easy to demonstrate that extra trumps don't automatically mean extra tricks. We will do it by showing you one deal and modifying it gradually. We start with 16 total trumps and end with 22 total trumps. If you expect the total tricks to vary accordingly, you are in for a big surprise. Just watch!
K Q 3 |
||
7 6 5 3 |
||
7 5 4 |
||
A 9 6 |
||
8 7 4 2 |
![]() |
5 |
K Q 2 |
A J 10 9 4 |
|
A 9 5 |
K Q J 3 |
|
8 6 4 |
10 7 5 |
|
A J 10 9 6 |
||
8 |
||
10 8 2 |
||
K Q J 3 |
K Q 3 2 |
||
7 6 5 |
||
7 5 4 |
||
A 9 6 |
||
8 7 4 |
![]() |
5 |
K Q 3 2 |
A J 10 9 4 |
|
A 9 5 |
K Q J 3 |
|
8 6 4 |
10 7 5 |
|
A J 10 9 6 |
||
8 |
||
10 8 2 |
||
K Q J 3 |
K Q 4 3 2 |
||
7 6 |
||
7 5 4 |
||
A 9 6 |
||
8 7 |
![]() |
5 |
K Q 5 3 2 |
A J 10 9 4 |
|
A 9 5 |
K Q J 3 |
|
8 6 4 |
10 7 5 |
|
A J 10 9 6 |
||
8 |
||
10 8 2 |
||
K Q J 3 |
K Q 7 4 3 2 |
||
7 |
||
7 5 4 |
||
A 9 6 |
||
8 |
![]() |
5 |
K Q 6 5 3 2 |
A J 10 9 4 |
|
A 9 5 |
K Q J 3 |
|
8 6 4 |
10 7 5 |
|
A J 10 9 6 |
||
8 |
||
10 8 2 |
||
K Q J 3 |
K Q 8 7 4 3 2 |
||
– |
||
7 5 4 |
||
A 9 6 |
||
– |
![]() |
5 |
K Q 7 6 5 3 2 |
A J 10 9 4 |
|
A 9 5 |
K Q J 3 |
|
8 6 4 |
10 7 5 |
|
A J 10 9 6 |
||
8 |
||
10 8 2 |
||
K Q J 3 |
So why did this swap result in two more total tricks while the previous swaps didn't change anything?
The answer is simple. The last swap removed one loser for North-South and one loser for East-West. In diagrams 1, 2, 3 and 4, the extra trumps didn't stop the opponents from cashing the first four tricks. It is also worth noting that in diagram 5, the extra tricks don't come from the extra trumps – they come from the fact that the defending side now only can take the first three tricks. For both sides, the extra tricks came from a reduction of losers. A singleton in the opponents' suit meant one loser there, while a void meant no losers. The explanation is in the distribution, NOT in the number of trumps.
We started with 16 total trumps and moved up to 24 total trumps. What do you think will happen if we move the last trumps too?
Yes, you're right. Any swap will add a trick – if, and only if the swap removes a loser. So if South gives his heart to West or East and gets a diamond in return, nothing happens since neither side got rid of a loser, but if South gets a club East-West gain a trick, as they now only lose two club tricks.
Deal No. 6.
K Q |
||
7 6 5 3 2 |
||
7 5 4 |
||
A 9 6 |
||
8 7 4 3 2 |
![]() |
5 |
K Q |
A J 10 9 4 |
|
A 9 5 |
K Q J 3 |
|
8 6 4 |
10 7 5 |
|
A J 10 9 6 |
||
8 |
||
10 8 2 |
||
K Q J 3 |
Let's make a new change from deal No 1, but this time we move two minor suit cards, not two trumps. We keep the total trumps at 16, but suddenly the total tricks go up...
K Q 3 |
||
7 6 5 3 |
||
7 5 |
||
A 9 6 4 |
||
8 7 4 2 |
![]() |
5 |
K Q 2 |
A J 10 9 4 |
|
A 9 5 4 |
K Q J 3 |
|
8 6 |
10 7 5 |
|
A J 10 9 6 |
||
8 |
||
10 8 2 |
||
K Q J 3 |
The Law of Total Tricks refers to what happens if each side plays in its "best trump suit", and here clubs play one trick better than spades for North-South, and diamonds play one trick better than hearts for East-West. So, the effect of our moving two minor suit cards was that (a) two tricks were added to the trick total, one for each side, and (b) both sides got a new "best trump suit". Now, these 16 total trumps take 20 total tricks; we have a +4 deal.
The reason why this swap gained one trick for North-South and one trick for East-West should be familiar to you by now. It is because both sides got rid of a loser. The fact that neither side gained a trump is insignificant.
This last swap shows another error in concentrating on the number of trumps: When one side (or both) have two or three trump suits of the same length, it is a not uncommon occurence that one of those suits will take more tricks than the other(s). Suppose you try to apply the Law of Total Tricks and know that the opponents have eight spades, the suit they are bidding. Can you be sure that they are competing in their best suit? If they have another trump suit (of the same length or longer), which will take one or two more tricks, any attempt to use the total tricks formula to guide you will result in failure.